[Solved] Genotypes and Phenotypes

Data Sheet: Activity – GeneticsAll Content is Copyright Protected and May NOT Be Posted or Shared Outside Of The ClassroomNameCourseDateActivity Data Code ?????Procedure I – Part A – Baby bugs when parents are BB and bb4TableTop Science – All Rights Reserved1TableTop Science – All Rights ReservedData Table – Enter your Baby Bug CountsBB Baby BugCountBb Baby BugCountbb Baby BugCountPercentage Tables – Enter the Baby Bug percentagesTip: Baby Bug Percentage = 100% (Baby Bug Count) / (Total Number of Baby Bugs)BB Baby BugPercentageBb Baby BugPercentagebb Baby BugPercentageTip: Blue Rimmed Baby Bug Percentage = BB Baby Bug Percent + Bb Baby Bug PercentBlue Rimmed Baby BugPercentageYellow Rimmed Baby BugPercentageObservations and Questions[1] Complete the Punnett square below when the parents are BB and bb.Punnett SquareMaleFemaleAlleles/GenesBB[2] Describe your baby bug results from this data run in terms of genotypes and phenotypes.[3] Why are there no BB baby bugs or bb baby bugs from this data run?[4] Do the results for the allele distributions confirm the entries in your Punnett Square? Please explain.[5] What evidence from this data run supports the hypothesis that the B allele is heterozygous dominant? Explain your reasoning.

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